a = 10

a //=3

print(a)

程序的输出结果是

for i in range(6):

    if i%2==0: continue

    elif i%3:

        print(i,end=' ')

        break

else:

     print('end')

a=[7,6,3,4]

print(sum(a))

def fun(n):

    if n == 1:

        return 1

    else:

        return fun(n-1)+1

print(fun(3))

a=[8,5,11]

b=list(reversed(a))

print(b)

for i in range(3,9):

    if i%2 == 0: 

       continue

    print(i,end =' ')