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下列对诗句的分析，不正确的一项是（）

下列对这首诗的理解与赏析，正确的一项是（）

下列对这首诗主旨的理解，最准确的一项是：（）

已知$$\omega$$是正整数，函数$$f(x)=\sin(\omega x+\omega)$$在$$(0,\omega\pi)$$内恰好有4个零点，其导函数为$$f'(x)$$，则$$f(x)+f'(x)$$的最大值为（）

已知非零空间向量$$\vec{a},\vec{b}$$，且$$\overrightarrow{AB}=\vec{a}+2\vec{b}$$,$$\overrightarrow{BC}=-5\vec{a}+6\vec{b}$$,$$\overrightarrow{CD}=7\vec{a}-2\vec{b}$$，则一定共线的三点是（）

已知等差数列$$\{a_n\}$$满足$$a_3+a_5=22$$，前8项和$$S_8=100$$；公比为正数的等比数列$$\{b_n\}$$满足$$b_4-b_2=12$$，$$b_3=8$$，设$$c_n=a_{b_n}$$，$$T_n$$为数列$$\{c_n\}$$的前$$n$$项和，则当$$T_n<2024$$时，$$n$$的最大值是（）

已知对任意正数$$a$$、$$b$$、$$c$$，当$$a+b+c=1$$时，都有$$2^a+2^b+2^c

若关于$$x$$的方程$$e^x=\frac{m(\ln x+x-1)}{x}$$有两个解，则实数$$m$$的取值范围为（）

已知椭圆$$\Gamma:\frac{x^2}{a^2}+\frac{y^2}{b^2}=1(a>b>0)$$的离心率为$$e$$，$$M$$为$$\Gamma$$的上顶点，$$P$$，$$N$$是椭圆$$\Gamma$$上不同于$$M$$的两点，若$$\triangle PMN$$是以$$M$$为直角顶点的等腰直角三角形，则满足条件的$$\triangle PMN$$有（） <此处为图片>（含图）

若圆$$C:(x-1)^2+(y+3)^2=1$$上存在两点$$A,B$$，直线$$l:3x-4y+m=0$$上存在点$$P$$，使得$$\angle APB=60^\circ$$，则实数$$m$$的取值范围为（）

<此处为图片> 对于C，将侧面$$ABB_1A_1,BCC_1B_1$$展开且处于同一平面，连接$$A_1C_1$$与$$A_1B_1$$交于点$$Q$$，如图所示，则$$\triangle AA_1Q\sim\triangle C_1B_1Q$$，所以$$\frac{A_1Q}{A_1B_1}=\frac{2}{3}$$，由上述结论可知，$$\angle A_1=\frac{2\pi}{3}$$，由余弦定理得，$$\cos A_1=\frac{4^2 + (\frac{4}{3})^2 - AQ^2}{2\times4\times\frac{4}{3}}$$，解得$$AQ=\frac{4\sqrt{13}}{3}$$，则$$CQ=\frac{1}{2}AQ=\frac{2\sqrt{13}}{3}$$，所以$$AC_1=AQ + QC_1=2\sqrt{13}$$，因为$$P$$为棱$$BB_1$$上的动点（含端点），所以点$$A,P,C_1$$不能共线，所以$$AP + PC_1>AC_1=2\sqrt{13}$$，故C错误；对于D，当点$$A,P,C$$共线时，$$AP + PC$$最短，由余弦定理得，$$\cos\angle ABC=\frac{36 + 36 - AC^2}{2\times6\times6}$$，解得$$AC=6\sqrt{3}$$，所以$$AP + PC$$的最小值为$$6\sqrt{3}$$，故D正确；故选：ABD. 【缺少答案，请补充】（含图）

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Which pack costs the least?

What is a feature of the Brick Challenge Calendar?

What does the author imply about the experience of reading King Lear?

What does the author think of John Cage's music at first?

What motivated the author to give John Cage's music a second listen?

What is the author trying to express in this article?

Why does Croom design the study?

Why does Croom mention judging a "pile of books" and a "bowling ball"?"